Bob Ware (16 Sep 2010)
"Obama, Methuselah, Sukkot, the Autumnal Equinox and Jesus Christ"

Some anomalies that link: Obama, Methuselah, Sukkot, the Autumnal Equinox, the elements found in nature, Jesus Christ, the first half of the Tribulation and eternity.
 

Three different gematrias for ‘Barack Hussein Obama’:

 

            ASCII code sum: 1795

 

            English: 793

 

            Hebrew: 501

 

The sum of the seven consecutive numbers: 2081 to 2087 equals the total number of elementary particles in the 92 elements found in nature. From 9.16.2010 to 9.22.2010 (Sukkot) will be the 2081st to the 2087th days since Obama was sworn into the U.S. Senate.

 

1795 plus 793 equals: 2588

 

2087 plus 501 equals: 2588

 

The Autumnal Equinox spans the two Gregorian dates: 9.22.2010 and 9.23.2010.

 

9.21.2010 will be the 4738th day of the current Jewish calendar cycle. 4738 equals 2 x the Greek gematria of ‘JESUS CHRIST’ (2368). When 4738 is the circumference of a circle then its radius is 754. 754 is the Hebrew gematria of Yehoshua HaMeshiach (JESUS CHRIST).

 

Methuselah lived 969 years. On 9.23.2010 Obama will have lived 969 days longer than JFK.

 

9.23.2010 will be 1260 days since the ‘FOREVER’ (eternity) stamp was released.

 

1143 is the sum of the ASCII codes for ‘Jesus Christ’. 1737 and 1143 are the two different sides of a rectangle with a perimeter of 5760 (4 x 1440). There are 1440 minutes in a day and 1440 is the diameter of the ‘Circle of Time’ where the date: 12.21.2005 falls at the top. 12.21.2005 plus 1737 days will be 9.23.2010.

 

On the third day of the Six Day War (6.7.1967) the Jews took control of the eastern Holy sites of Jerusalem. From 6.5.1967 to 9.23.2010 will be:15,814 days. 15,814 degrees equals 276 radians. 276 were saved in Paul’s shipwreck.