1795 is the sum of the ASCII codes for ‘Barack Hussein
Obama’. From 12.21.2005 to 11.20.2010 will be 1795
days. On 11.20.2010 Obama will have 793
inclusive days remaining in office. 793
is the English gematria of ‘BARACK HUSSEIN OBAMA’. From 11.20.2010 the remaining distance to the bottom
of the circle is 467. 467 is the center point of the ‘Prime Cross’ and
it is the sum of the three different gematrias for ‘God’ (86
Hebrew + 99 Prime + 282
ASCII). From the only crash of the Concorde, that killed 113 people, to 11.20.2010 will be 3770
days. 3770 equals five of the 60 degrees arcs around
this ‘Circle of Time’. 3770 also equals the sum of the ASCII codes for
‘John Fitzgerald Kennedy’ (2153) plus ‘George Walker Bush’
(1617).
The sum of the five years in the unique
‘leap-year/twin-prime’ cluster of years from 1996 to 2000 equals 9990. This is the total gematria of both the
Hebrew and Greek alphabets - including all their finals. The center date between 1.1.1996 and
12.31.2000 was 7.2.1998. From this center date of 7.2.1998 to 11.20.2010 will be 4524
days. 4524 is the circumference of the ‘Circle of
Time’.
The arc from the top of the circle to 11.21.2010 spans 1796
days. When the circumference of the circle is divided into the 1440
minutes in day then this arc equals 572
minutes. 1796 plus 572
equals: 2368 which is the Greek gematria of ‘JESUS
CHRIST’. The length of the remaining arc to the bottom of the circle is 466.
This is the gematria of the second
name on the breastpiece: Simeon. The combined lengths of the two radius lines, from the center of the circle to each end of
this arc, total 1440 which is the number of minutes in a day. 1440 +
466 equals: 1906
which was the year of the San Francisco earthquake.
The following day will be 11.22.2010. This will be the 47th
anniversary of the assassination of JFK. From 11.22.2010 to 12.21.2012 will be 760 days. 760 plus the length
of the radius line pointing to 12.21.2012 equals 1480. This is the Greek gematria of ‘CHRIST’.
This curved arc and straight radius line form the shape of a sickle used in harvesting. I hope this means that
Christ will begin the harvesting of
His children on (or before) 11.22.2010.
11.22.2010 will be the 4800th day of the current 19-year
Jewish calendar cycle. The decimal number 4800 equals the octal number 11300 (100 x 113).
113
is the first point of the ‘Prime Cross’. 113 x
Pi equals the 355 days in 12 lunar cycles. 355
is the maximum number of days in one normal Jewish year. 4800 also equals the circumference of the
‘Circle of Time’ (4524) plus the 276
saved in Paul’s shipwreck. When 4800 is the circumference of a circle then the
length of each side of the square within the circle is 1080. 1080
is the gematria of the ‘THE HOLY SPIRIT’. 1080
is also the height of the triangles within the ‘Circle of Time’ and the number
of days in three prophetic years.
The length of the remaining arc from 12.21.2012 back to the top of the circle is 1967.
The length of each side of the two triangles within this ‘Circle of Time’ is
1247. Radius lines passing through the center of these six triangle sides will
make six symmetrical crosses – one for each day of the 1967
Six Day War. 1247 plus the radius line of 720 passing through its center totals 1967.
It appears that the three consecutive days from 11.20.2010 to 11.22.2010 are all connecting: Jesus Christ, Barack Obama and JFK and then, ultimately pointing to the Mayan date of 12.21.2010.
