Bob Ware (5 May 2008)
"3368 Gematria of LORD JESUS CHRIST returns 2701 and 3 January 2010"

John -
 
The gematria of three Greek words 'LORD JESUS CHRIST' equals 3368. A triangle has three sides. Draw a circle around a triangle that has a perimeter of 3368. Now draw a square and a golden rectangle within this same circle. Each side of the square will be 916.653. The two different sides of the golden rectangle will be: 681.513 and 1102.711. The sum of these three different values is: 2700.877 or 2701.
 
The diameter of this circle is 1296 which equals 36 x 36. The 36th triangle number is 666 and the sum of the four points of the overall prime cross is 3636.
 
The area of each one-degree segment of this circle is 3,666. I consider that each one-degree segment represents one prophetic day since there are 360 degrees in a circle and 360 days in one prophetic year. I began numbering the last days for the Body of Christ from the Winter Solstice of 5760 (12/22/1999). Thus, Solstice day number 3,666 will be 3 January 2010. This will be the 7104 day of the current 30-year Islamic calendar cycle. 7104 equals 8 x 888.
 
Go counter clockwise 754 days/units of measurement from the date at the top of this simple 'Circle of Time' chart and you will come to a Star of David point labeled with the date 3 January 2010. Thus, 11 December 2007 plus 754 days will be 1 January 2010. Each 60-degree arc around the 'Circle of Time' is 754 (754 x 6 equals the 4524 days from 2 August 2000 to Mayan date 21 December 2012). 754 = Yehoshuah HaMaschiach. 2 August 2000 > 2/8/00 > 2800 = gematria of the first verse in the Bible (2701) + the gematria of the last word 'Amen' (99).
 
- Bob
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Bob,
7104 is also 3 x 2368 (Jesus Christ)
John