from: http://neo.jpl.nasa.gov/
http://neo.jpl.nasa.gov/cgi-bin/neo_ca?type=NEO;hmax=all;tlim=recent_future;dmax=0.1AU;max_rows=200;action=Display%20Table;show=1&sort=dist_min&sdir=ASC

"73P/Schwassmann-Wachmann 3-BD 2006-May-11 21:53 ± 11:11 0.04/0.00010"

The minimum "miss distance" is listed as "0.04/0.00010" LD/AU

_Analysis:_

*since 1 AU* = 149,597,870.691 kilometers, this comet's 0.00010 AU would
be only 14,959.8 km min distance near-miss of earth.

Then, according to this site,
http://www.asterism.org/tutorials/tut25-1.htm, it says "The Earth's
Roche limit for comets is 34,700 km."

So, what I don't understand is since this comet's projected min distance
is only about 15,000 km, and that is well within the 34,700 km "roche
limit," is the comet going to break up and crash into the earth?!

Also, if the comet is only 15,000 km away from the center of the earth,
then it is only 11,000 km away from the surface, isn't that pretty close
when you add gravity to pull it down?

Any math-science doves with insight please help!

- M