Phil (22 July 2011)
"Re Beverley's "Elenin's Arrival""

John and Doves,

Hi Beverley. I don't know when Elenin or whatever it really is will be visible but I just noticed
that on Aug 4th it crosses the Earth's orbit and is 1.476AU from the Earth.

http://ssd.jpl.nasa.gov/sbdb.cgi?sstr=C%2F2010%20X1;orb=1;cov=0;log=0;cad=0#phys_par

1,476 is 36 x 41 or 18 x 82 or (6+6+6) x 82

1,476 is also 123 x 12 or 123 x (6+6)

Aug 4th is Obama's birthday on day #216 and he will be 50 this year.

216 = 36 x 6 or 18 x 12 or (6+6+6) x (6+6)

216/50 = 4.32 or 234 backwards.

On Aug 4th it will be 0.984AU from the sun.

984 = 123 x 8.

So, on Aug 4th, Elenin is exactly 1.5 times further away from the Earth than the sun. 1.476/0.984 = 1.5.

1+4+7+6 = 18.

From Aug 4th (crosses Earth orbit) to Oct 17th (closest to Earth and crosses Earth's orbit) is 74 days or 2 x 37.

On Oct 17th it will be 0.232AU from Earth and 0.956AU from the sun.

232 + 956 = 1188 and 1+1+8+8 = 18.

1188 = (6+6+6) x 66. Mmmmm.

Interesting.

Keep looking up,

Phil.